Question

Find the sum of first 25 terms of the sequence 16,24,32​

Answer 1

Answer:

a = 16

d = 24-16 = 8

Let number of terms = n

Sn =n{2xa+n-2xd } /2

=n{2x16+(n-1)x8}

= n(12 + 4n)

Sn + 9 = 4n2 + 12n + 9 = (2n + 3)2

Hence, the sum of any number of terms of the arithmetic sequence 16, 24, 32, …. starting from the first, added to 9 gives a perfect square

Answer 2

Answer:

2800 hope It is helpful