Question

Find the sum of first 250 positive integers

Answer 1

Answer:S 250=250 /2(2×1 +(250-1)1)

= 250/2(2+249)

125×251=28855

Step-by-step explanation:use Sn= n/2(2a+ (n-1)d)

Answer 2

Answer:

Sum of first 250 positive integers is 31375.

Step-by-step explanation:

We know that Sum of first n terms of series is given by;

                         $S_n = \frac{n}{2} [2a+(n-1)d]$

where, n = number of terms

            a = first term of the series

            d = common difference

So, In first 250 positive integers first term, a = 1  and common difference,d=1

Therefore, $S_2_5_0 = \frac{250}{2} [2*1+(250-1)*1]$

                          = 125*(2 + 249) = 125 * 251 = 31375

Hence, sum of first 250 positive integers is 31375.