Question

find the sum of first 28 terms of an ap whose nth term is 4n-3​

Answer 1

Answer:

here is ur answer✌️

n=28

tn= 4n-3

t1=4×1-3=1

t2=4×2-3=5

t28=4×28-3

=112-3=109

a =1,

d=t2-t1

=5-1

=4

l=109

Sn=n/2 (2a+(n-1)d)

S28=28/2(2×1+27×4)

=14(2+108)

=14×110

=1540

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Answer 2

Answer:

n=28

tn= 4n-3

t1=4×1-3=1

t2=4×2-3=5

t28=4×28-3

=112-3=109

a =1,

d=t2-t1

=5-1

=4

l=109

Sn=n/2 (2a+(n-1)d)

S28=28/2(2×1+27×4)

=14(2+108)

=14×110

=1540

Step-by-step explanation:

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