Question

find the sum of first 30 positive integers divisible by 8​

Answer 1

Answer:

Step-by-step explanation:

Address the formula, input parameters & values.

Input parameters & values:

The number series 8, 16, 24, 32, 40, 48, 56, 64, 72, 80, 88, 96, .  .  .  .  , 240.

The first term a = 8

The common difference d = 8

Total number of terms n = 30

step 2 apply the input parameter values in the AP formula

Sum = n/2 x (a + Tn)

= 30/2 x (8 + 240)

= (30 x 248)/ 2

= 7440/2

8 + 16 + 24 + 32 + 40 + 48 + 56 + 64 + 72 + 80 + 88 + 96 + .  .  .  .   + 240 = 3720

Therefore, 3720 is the sum of first 30 positive integers which are divisible by 8

Answer 2

hi mate!

your answer,

a=8, d=8, S30=?

S30=30/2[2×8+(30-1) 8]

=15[16+29×8]

=15[16+232]

=15×248

=3720

hope that it will help you