Question

find the sum of first 30 term of the arithmetic Sequence 10,16,22_______. *​

Answer 1

Given :-

AP = 10,16,22

To Find :-

30th term

Solution :-

We know that

aₙ = a + (n - 1)d

a = First term = 10

d = common difference

= Second term - First term

= 16 - 10

= 6

By puuting values

a₃₀ = 10 + (30 - 1)6

a₃₀ = 10 + (29)6

a₃₀ = 10 + 174

a₃₀ = 184

Hence

30th term is 184

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Answer 2

2910.

Step-by-step explanation:

You know this formulae, right? Sum of first ' n ' numbers of an A.P....

$\frac{n}{2} \times (2a + (n - 1)d)$

Substitute the values

Write the steps

Have a nice day.