find the sum of first 30 terms of the series 4+7+10+....
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Answer:
The terms,
4,6,8,10
form an AP with a=4 and d=2 giving the terms:
a=4,a+d=6,a+2d=8,...
Then the sum of the first n-terms is
Sn=n2{2a+(n−1)d}
So
S50=502{2⋅4+49⋅2}
=15{8+98}
=15{106}
=1590
Explanation:
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