Find the sum of first 35 term of the series whose pth term is p/7+2
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Answered by
2
as the p th term is p/ 7 +2
thus first term will be 1/7 +2
and similarly second term will be 2/7 +2 on subtracting from a2 we get A2
1/7 which is d
s35 = 35/2(15/7+34*1/7)
= 35/2(49/7)
=17.5(7)
= 122.5
hope this might help you
thus first term will be 1/7 +2
and similarly second term will be 2/7 +2 on subtracting from a2 we get A2
1/7 which is d
s35 = 35/2(15/7+34*1/7)
= 35/2(49/7)
=17.5(7)
= 122.5
hope this might help you
Answered by
3
sum = n/2( a+l)
number of terms
a= 1st term
l = last term
a= 1/7 +2
l = 35/7 +2
n=35
S= 35/2 ×(1/7+ 2 + 35/7 +2)
==35/2 × (36/7 +4)
==35/2 ×64/7
==5×32
==160
so sum 35 terms is 160.
number of terms
a= 1st term
l = last term
a= 1/7 +2
l = 35/7 +2
n=35
S= 35/2 ×(1/7+ 2 + 35/7 +2)
==35/2 × (36/7 +4)
==35/2 ×64/7
==5×32
==160
so sum 35 terms is 160.
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