find the sum of first 35 terms of the series whose pth term is p/7+2
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Answered by
1
Pth term = p/7 +2
So the sum of p terms will be ((p×(p+1)/7) + 2p
Therefore for 35, the sum will be
35×36/7 + 2 ×35
5 × 36 + 2 ×35
180 + 70
250
Answer is 250
So the sum of p terms will be ((p×(p+1)/7) + 2p
Therefore for 35, the sum will be
35×36/7 + 2 ×35
5 × 36 + 2 ×35
180 + 70
250
Answer is 250
dainvincible1:
ur answer is wrong
Answered by
6
a₁ = (1/7) + 2 = 15/7
a₂ = (2/7) + 2= 16/7
a₃ = (3/7) + 2 = 17/7
a₃₅ = (35/7) + 2
a₃₅ = 49/7
⇒ 35/2 {15/7 + 49/7}
⇒ 35/2 (64/7)
⇒ 160
∴ The sum of first 35 terms of the series whose pth term is p/7+2 is 160
a₂ = (2/7) + 2= 16/7
a₃ = (3/7) + 2 = 17/7
a₃₅ = (35/7) + 2
a₃₅ = 49/7
⇒ 35/2 {15/7 + 49/7}
⇒ 35/2 (64/7)
⇒ 160
∴ The sum of first 35 terms of the series whose pth term is p/7+2 is 160
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