Question

find the sum of first 40 multiples of6​

Answer 1

Answer:

=4920

Step-by-step explanation:

ap=6,12,18,......240

a=6

d=6

n=40

an=240

S40=n/2(2a+(n-1)d)

      =40/2(2(6)+(40-1)6)

      =20(12+234)

      =20(246)

      =4920.

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Answer 2

Answer:

4920

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