find the
sum of first 40 natural numbers
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formula for sum of first n natural numbers is (n×(n+1))÷2
here n =40 so sum is 820
here n =40 so sum is 820
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First 40 natural numbers:
1,2,3 .........40.
Sum of n natural numbers.
Sn = [ n ( n + 1 )/ 2 ]
here,
n = 40
S40 = [ 40 ( 40 + 1 )/ 2 ]
= 20 × 41
= 820
1,2,3 .........40.
Sum of n natural numbers.
Sn = [ n ( n + 1 )/ 2 ]
here,
n = 40
S40 = [ 40 ( 40 + 1 )/ 2 ]
= 20 × 41
= 820
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