Question

Find the sum of first 40 positive integers divisible by 6

Answer 1

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Answer 2

Answer:

The first 40 positive integers divisible by 6 are 6,12,18,...,240

Therefore, a=6, d=6, l=240, n=40

Therefore, Sn=n/2(a+l)

=40/2(6+240)

=20x246

=4920