find the sum of first 40 positive integers divisible by 8
Answers
Answered by
4
Answer:
Therefore, 6560 is the sum of first 40 positive integers which are divisible
Step-by-step explanation:
step 1 Address the formula, input parameters & values.
Input parameters & values:
The number series 8, 16, 24, 32, 40, 48, 56, 64, 72, 80, 88, 96, . . . . , 320.
The first term a = 8
The common difference d = 8
Total number of terms n = 40
step 2 apply the input parameter values in the AP formula
Sum = n/2 x (a + Tn)
= 40/2 x (8 + 320)
= (40 x 328)/ 2
= 13120/2
8 + 16 + 24 + 32 + 40 + 48 + 56 + 64 + 72 + 80 + 88 + 96 + . . . . + 320 = 6560
Therefore, 6560 is the sum of first 40 positive integers which are divisible
Similar questions