Question

find the sum of first 40 positive number divisible by 6​

Answer 1

Answer:

4920

Step-by-step explanation:

40th multiple of 6  = 240

We need to find..

6+12+18...240

Taking 6 common

6(1+2+3+4...40)

=6.40.41/2                  [Since the sum of the first n natural numbers is n(n+1)/2]

=4920