Math, asked by SantoshiSutar, 11 months ago

find the sum of first 40 terms divisible by 6??

Answers

Answered by Tamilneyan

1

Answer:

sum = 4920

Step-by-step explanation:

Attachments:

Answered by sweetysinghal7109

2

Answer:The answer is 4920

Step-by-step explanation:

6+12+18................+40 terms

D=6, n=40, a=6

Sn =n÷2 [2a+(n-1)d]

S40=40÷2 [2×6(40-1)×6]

=20 [12×234]

=20×246

=4920

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