Question

find the sum of first 49 numbers of the AP is 2,4,6,8....​

Answer 1

Answer:

1. s =n/2(2a+(n-1)d)
2. n=49,a=2,d=2
3. after putting all these values
4. s=2450

Answer 2

Step-by-step explanation:

a=2. d=4-2=2. n=49. Sn=?

Sn= n/2[2a+(n-1)d]

=49/2[2(2)+(49-1)2]

=49/2[4+96]

=49/2[100]

=49[50]

= 2450

Sum of first 49 number of AP is 2450