Question

Find the sum of first 5 positive integers divisible by 6.​

Answer 1

Answer:

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Here is your answer

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The no. of list which is divisible by 6 ..are

6 , 12 , 18 , 24, and 30

Use the formula of Sum of Term of AP

Sn = n/2[a + l ]

n = 5 , a = 6 and l ( last term) = 30

\begin{gathered} \frac{n}{2} (a + l) \\ \\ \frac{5}{2}(6 + 30 ) \\ \\ \frac{5}{2} \times 36 \\ \\ 5 \times 18 \\ \\ 90\end{gathered}

2

n

(a+l)

2

5

(6+30)

2

5

×36

5×18

90

There the sum of 5 positive integer which are divisible by 6 is 90 ..

Answer 2

Answer:

6 + 12 + 18 + 24 + 30 = 90

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