Find the sum of first 5 positive integers divisible by 6.
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The no. of list which is divisible by 6 ..are
6 , 12 , 18 , 24, and 30
Use the formula of Sum of Term of AP
Sn = n/2[a + l ]
n = 5 , a = 6 and l ( last term) = 30
\begin{gathered} \frac{n}{2} (a + l) \\ \\ \frac{5}{2}(6 + 30 ) \\ \\ \frac{5}{2} \times 36 \\ \\ 5 \times 18 \\ \\ 90\end{gathered}
2
n
(a+l)
2
5
(6+30)
2
5
×36
5×18
90
There the sum of 5 positive integer which are divisible by 6 is 90 ..
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0
Answer:
6 + 12 + 18 + 24 + 30 = 90
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