Find the sum of first 5 terms of the geometric series 2 + 2/3 + 2/5 +........
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sum of first 5 term is S5= 2( root 3 ) raise to the power 4 -1 / root 3-1, 2(9-1)/ root 3-1, 2(8)/ root 3-1, 16/ root 3-1 by rationalise 16(root 3+1)/2, 8( root 3+1) this is answer ( please mark it as a brainiest)
anurag109:
Please mark it as a brainiest
Answered by
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Heya friends.☣
Here is ur answer...↙
a' first term =2
second term.t2 =2/3
common difference between two consecutive term is t2-t1
so,2/3-2
d=2-6/3
d'=-4/3
t5=a+4d
t5=2+4*(-4)/3
=>6-16
-----------
3
=>-10/3
⬅⬅⬅⬅⬅⬅⬅⬅⬅⬅⬅⬅⬅⬅⬅⬅
now as you know that....the sum of nth term of an Ap is n/2(a+l)
【where a is first term and l is last term】
=>5/2【2+(-10/3)】
=>5/2【6-10)/3】
=>5/2【18-10)/3】
=>【5/2(8)/3】
=>40/6
=>20/3 Ans .
Hope it help you..
@Rajukumar☺☺
Here is ur answer...↙
a' first term =2
second term.t2 =2/3
common difference between two consecutive term is t2-t1
so,2/3-2
d=2-6/3
d'=-4/3
t5=a+4d
t5=2+4*(-4)/3
=>6-16
-----------
3
=>-10/3
⬅⬅⬅⬅⬅⬅⬅⬅⬅⬅⬅⬅⬅⬅⬅⬅
now as you know that....the sum of nth term of an Ap is n/2(a+l)
【where a is first term and l is last term】
=>5/2【2+(-10/3)】
=>5/2【6-10)/3】
=>5/2【18-10)/3】
=>【5/2(8)/3】
=>40/6
=>20/3 Ans .
Hope it help you..
@Rajukumar☺☺
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