Math, asked by ares83, 7 months ago

find the sum of first 50 natural numbers​

Answers

Answered by Anonymous
3

Answer:

address the formula, input parameters & values.

Input parameters & values:

The number series 1, 2, 3, 4, . . . . , 49, 50.

The first term a = 1

The common difference d = 1

Total number of terms n = 50

step 2 apply the input parameter values in the formula

Sum = n/2 x (a + Tn)

= 50/2 x (1 + 50)

= 2550/2

1 + 2 + 3 + 4 + . . . . + 49 + 50 = 1275

Therefore, 1275 is the sum of positive integers upto 50.

Answered by Anonymous
6

Answer:

GIVEN....

SUM OF FIRST 50 NATURAL NUMBERS......

1+2+3+4+5........50=1275

THEREFORE 1275 IS THE SUM OF 1ST 50 NATURAL NUMBERS

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