find the sum of first 50 terms of the 1/2 1/4 1/8
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Answer:
a2=14, a3=18
a+2d=14-----(1)
a+2d=18-----(2)
Subtract equation (1) and (2)
Therefore d=2
Since, a+d=14 , a+4=14.
Therefore, a=10
Therefore, Sn=n/2[2a+(n-1)d]
S15=50/2[2x10+(5-1)x4]
=50/2(20+200)
=50/2x220
=5500
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