Question

find the sum of first 50 terms of the AP 1, 11 ,21 ,31 ​

Answer 1

Answer:

n = 50, a=1

d( common diff ) = 11-1 = 10

$sn = n \div 2(2a + (n - 1)d)$

sn=50÷2(2×1+(50-1)10)

=25(2+490)

=25(492)

=11550

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