Question

Find the sum of first 50 terms of the arithmetic sequence 5,8,11,…

Answer 1

Answer:

3925

Step-by-step explanation:

Sum of an arithmetic progression:

S = $\frac{n}{2} (2a+[n-1]d)$

where,

n = number of terms = 50

a = first term = 5

d = common difference = 8 - 5 = 3

So, on substituting,

S = $\frac{50}{2} (2*5+[50-1]3)$

= $25 (10+49*3)$

= $25 (10+147)$

= $25*157$

= 3125

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