Question

find the sum of first 51 term of an Ap whose second and third term are 14 and 18 respectively​

Answer 1

Answer:

Step-by-step explanation:

A2= a+d = 14...........(1)

A3= a+2d=18..........(2)

Subtract (2)-(1), we get

-d = -14

d=14

Put value of d in eq (1), we get

a=10

S51 = 51/2(2×10+(50)4

= 51/2(220)

=51×110

= 5610

Answer 2

Answer:

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