Math, asked by pakaramchoudhay42, 6 months ago

find the sum of first 57even natural number​

Answers

Answered by karanmange276
0

Answer:

Take mate

Step-by-step explanation:

step 1 Address the formula, input parameters & values.

Input parameters & values:

The number series 2, 4, 6, 8, 10, 12, . . . . , 114.

The first term a = 2

The common difference d = 2

Total number of terms n = 57

step 2 apply the input parameter values in the AP formula

Sum = n/2 x (a + Tn)

= 57/2 x (2 + 114)

= (57 x 116)/ 2

= 6612/2

2 + 4 + 6 + 8 + 10 + 12 + . . . . + 114 = 3306

Therefore, 3306 is the sum of first 57 even numbers.

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