find the sum of first 57even natural number
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Answer:
Take mate
Step-by-step explanation:
step 1 Address the formula, input parameters & values.
Input parameters & values:
The number series 2, 4, 6, 8, 10, 12, . . . . , 114.
The first term a = 2
The common difference d = 2
Total number of terms n = 57
step 2 apply the input parameter values in the AP formula
Sum = n/2 x (a + Tn)
= 57/2 x (2 + 114)
= (57 x 116)/ 2
= 6612/2
2 + 4 + 6 + 8 + 10 + 12 + . . . . + 114 = 3306
Therefore, 3306 is the sum of first 57 even numbers.
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