Question

find the sum of first 6 terms of G.P. 1, - 1/3 , 1/9 , -1/27
plz answer correctly n ASAP

Answer 1

$hey \: here \: is \: ur \: ans \\ \: sum \: \: of \: first \: 6 \: terms = a(1 - r {}^{n} ) \div (1 - r) \\ a = 1 \: n = 6 \: \: r = - 1 \div 3 \\ so \: 1(1 - ( - 1 \div 3) {}^{6} ) \div ( 1 + 1 \div 3) \\ = 546$