Find the sum of first 61 even natural numbers
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Answered by
4
The series will be
2,4,6,8,10........to 61th
First term=2
Common difference=2
Sum of 61 even natural numbers=61/2×[2×2+(61-1)2]
=61/2×[4+120]
=61/2×[124]
=61×62
=3782
#May_i_come_in?
Aham brahamasam
Answered by
3
Step-by-step explanation:
a = 2
d = 2
sum of all first 61 even natural number =
s = n/2{2a+(n-1)d}
= 61/2 (2×2+60×2)
= 61/2 × 124
= 61×62
= 3782..
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