Question

Find the sum of first 65 terms of an AP 0.6,1.7,2.8.....

Answer 1

Answer:

The sum of the first 65 terms of an A.P 0.6,1.7,2.8... is 2327.

Step-by-step explanation:

Here, the common difference (d)= 1.1

                   A.P = 0.6,1.7,2.8...

                  first term (a)= 0.6 and n= 65

    Sn= n/2[2a+(n-1)d]

     S65= 65/2[2(0.6)+(65-1)1.1]

            = 65/2[1.2+71.5-1.1]

            = 32.5[1.2+70.4]

            = 32.5[71.6]

            = 2327

 Hence, the sum of the first 65 terms of an A.P 0.6,1.7,2.8... is 2327.                          

Answer 2

the answer for this ap is S=2327