find the sum of first 7terms of ap 10,6,2
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a = 10,d = 6-10= -4, n = 7
So,a7 = a+6d
a7 = 10+6×-4 = 10-24 = -14
Hence,
S7 = n/2(a+a7)
S7 = 7/2(10-14)
S7 = 7×-2
S7 = -14
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