find the sum of first 8 multiple of 3
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3+6+9+12+15+18+21+24 = 108
Smartymangesh:
Simply s8=8/2[2×3+8-1×3] solving it you get thr answer 108 where,a=3 and d=3
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Sum refers to the addition operation.
Multiples of a number is the number which is divisible by the number and by 1.
Hence, the first 8 multiples of three would be,
3*1=3
3*2=6
3=3=9
3*4=12
3*5=15
3*6=18
3*7=21
3*8=24
The multiples are 3,6,9,12,15,18,21,24.
Hence their sum,
3+6+9+12+15+18+21+24= 108
The answer is 108.
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