Question

find the sum of first 8 multiple of 3

Answer 1

in multiples of three.
a=3.

a8=3×8=24.

d=3

To Find S8

So S8=
$\frac{8}{2} (a + a8) \\ = 4(3 + 24) \\ = 4 \times 27 \\ = 108$
Hope it helps...

Regards,
Leukonov.

Answer 2

✨✔️Question : Find the sum of the first 8 multiples of 3.

•Formula used in this question :
$(s)n \: = \: \frac{n}{2} \: \times (a \: + \: {a}n)$


✔️✔️Answer:

First 8 Multiples of 3 = 3, 6, 9, 12, 15, 18, 21, 24.
a = 3
an = 24
n = 8

$(s)n \: = \: \frac{8}{2} \: \times \: ( 3 \: + \: 24)$

$(s)n \: = \: 4 \: \times \: 27$

$(s)n \: = \: 108$

Therefore, sum of the first 8 multiples of 3 is 108.

✨✔️HOPE IT HELPS YOU....
✌✌