find the sum of first 8 multiple s of 3
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3
first eight multiples of 3
3,6,9,12,15,18,21,24
sum of multiples=108
3,6,9,12,15,18,21,24
sum of multiples=108
Answered by
3
This is a question of AP.
First term would be 3.
Last term would be 3 × 8 = 24.
Total terms are 8 (given).
Using Sn formula:
Sn = n/2(a + l)
l = last term = 24
S8 = 8/2 ( 3 +24)
S8 = 4×27 = 108.
Your required answer is 108.
Hope you understood my answer. If yes please mark me as the brainliest.
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