find the sum of first 8 multiples of 3
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The first 8 multiples of 3 are : 3,6,9 …..24
Here, first term(a) = 3, common difference (d) = 3 , last term(l) = 24, number of terms (n) = 8
Sn = n/2(a+ l)
S8 = 8/2 (3+24)
S8 = 4 × 27
S8 = 108
Hence, the sum of first 8 multiples of 3 is 108.
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Here, first term(a) = 3, common difference (d) = 3 , last term(l) = 24, number of terms (n) = 8
Sn = n/2(a+ l)
S8 = 8/2 (3+24)
S8 = 4 × 27
S8 = 108
Hence, the sum of first 8 multiples of 3 is 108.
HOPE THIS WILL HELP YOU...
Answered by
0
Sum refers to the addition operation.
Multiples of a number is the number which is divisible by the number and by 1.
Hence, the first 8 multiples of three would be,
3*1=3
3*2=6
3=3=9
3*4=12
3*5=15
3*6=18
3*7=21
3*8=24
The multiples are 3,6,9,12,15,18,21,24.
Hence their sum,
3+6+9+12+15+18+21+24= 108
The answer is 108.
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