Question

find the sum of first 8 multiples of 3

Answer 1

The first 8 multiples of 3 are : 3,6,9 …..24
Here, first term(a) = 3, common difference (d) = 3 , last term(l) = 24, number of terms (n) = 8
Sn = n/2(a+ l)
S8 = 8/2 (3+24)
S8 = 4 × 27
S8 = 108
Hence, the sum of first 8 multiples of 3 is 108.

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Answer 2

Sum refers to the addition operation.

Multiples of a number is the number which is divisible by the number and by 1.

Hence, the first 8 multiples of three would be,

3*1=3

3*2=6

3=3=9

3*4=12

3*5=15

3*6=18

3*7=21

3*8=24

The multiples are 3,6,9,12,15,18,21,24.

Hence their sum,

3+6+9+12+15+18+21+24= 108

The answer is 108.

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