Find the sum of first 8 multiples of 3?
Answers
Answered by
13
Hey there!
First 8 multiples of 3 = 3 , 6 , ... , 24 .
Sum of first 8 multiples of 3 = 3 + 6 + 9 + .........+ 24 = 3 ( 1 + 2 + ... + 8 )
Now,
Sum of first 8 multiples of 3
= 3 [ 1 + 2 + ... + 8 ]
= 3[ 8(9)/2 ]
= 3 [4]9
= 108 .
Sum of first 8 multiples of 3 = 108
First 8 multiples of 3 = 3 , 6 , ... , 24 .
Sum of first 8 multiples of 3 = 3 + 6 + 9 + .........+ 24 = 3 ( 1 + 2 + ... + 8 )
Now,
Sum of first 8 multiples of 3
= 3 [ 1 + 2 + ... + 8 ]
= 3[ 8(9)/2 ]
= 3 [4]9
= 108 .
Answered by
11
Sum refers to the addition operation.
Multiples of a number is the number which is divisible by the number and by 1.
Hence, the first 8 multiples of three would be,
3*1=3
3*2=6
3=3=9
3*4=12
3*5=15
3*6=18
3*7=21
3*8=24
The multiples are 3,6,9,12,15,18,21,24.
Hence their sum,
3+6+9+12+15+18+21+24= 108
The answer is 108.
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