find the sum of first 8 multiples of 3
Khushiakherajot:
108 maybe
yeah u r ryt
Answers
Answered by
30
AP ; 3, 6 .....
Sn = n/2 [2a + (n-1) d] = 8/2 [2(3) + (8 - 1) 3
Sn = 4 [6 + 21] = 4 * 27 = 108
Sn = n/2 [2a + (n-1) d] = 8/2 [2(3) + (8 - 1) 3
Sn = 4 [6 + 21] = 4 * 27 = 108
u were using Ap formula
yea...
thank you soo much
re . exam of mathematics is held or not
it will held
only in Delhi and Haryana.......
yaa
and what about in Patna
Answered by
13
The first eight multiple of 3 are 3 , 6 , 9 , 12 , 15, 18 , 21 ,24
So their sum will be 3+6+9+12+15+18+21+24
= 108
Hope this helps you!!!!
Please mark this as the Brainliest
So their sum will be 3+6+9+12+15+18+21+24
= 108
Hope this helps you!!!!
Please mark this as the Brainliest
Thnx
thanks:-)
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