Question

find. the. sum. of. first 8. multiples. of. 3

Answer 1

HEY MATE !!

the sum of first multiple of 3

is =

AP => 3, 6,9 .....

n=> 8

d => 6-3 => 3

now ,

sn => n/ 2 ( 2a+ (n-1) d

=> 8/2 ( 2*3 + ( 8-1) *3

4 ( 6 + 21 )

=> 4* 27

=> 108 .

hope it helps D

thanks

Answer 2

Sum refers to the addition operation.

Multiples of a number is the number which is divisible by the number and by 1.

Hence, the first 8 multiples of three would be,

3*1=3

3*2=6

3=3=9

3*4=12

3*5=15

3*6=18

3*7=21

3*8=24

The multiples are 3,6,9,12,15,18,21,24.

Hence their sum,

3+6+9+12+15+18+21+24= 108

The answer is 108.

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