Question

Find the sum of first 8 multiples of 3

Answer 1

First 8 multiples of 3 are = 3 6 9 12 15 18 21 24
Now sum means add
+3+ 6+ 9 +12 +15 +18 +21 + 24 = 108
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Answer 2

Hey mate !!

here is your answer !!

ap = 3, 6 , 9...


now

a= 3


d = 6-3 = 3


now the sum of multiple of 3


we get


sn = n / 2 + ( 2a + (n-1) d )


sn = 8/2 ( 2*3 + (8-1) *3 )


sn => 4 * 27

=> 108

hope it helps:D


thanks