Question

find the sum of first 8 multiples of 3.

Answer 1

3+6+9+12+15+18+21+24=108
I think so

Answer 2

✨✔️Question : Find the sum of the first 8 multiples of 3.

•Formula used in this question :
$(s)n \: = \: \frac{n}{2} \: \times (a \: + \: {a}n)$


✔️✔️Answer:

First 8 Multiples of 3 = 3, 6, 9, 12, 15, 18, 21, 24.
a = 3
an = 24
n = 8

$(s)n \: = \: \frac{8}{2} \: \times \: ( 3 \: + \: 24)$

$(s)n \: = \: 4 \: \times \: 27$

$(s)n \: = \: 108$

Therefore, sum of the first 8 multiples of 3 is 108.

✨✔️HOPE IT HELPS YOU....
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