find the sum of first 8 multiples of 3
Answers
Answered by
7
hey.....here's your answer...!!
8 + 16 +24+ 32 + 40 + 48 + 56 + 64 = 288..
Hope this helps..!!
8 + 16 +24+ 32 + 40 + 48 + 56 + 64 = 288..
Hope this helps..!!
riddhi66:
sorry I misunderstood d question...
the right procedure is as follows...
3 + 6 + 9 + 12 + 15 + 18 + 21 + 24 = 108.
hope this helps..!?
Answered by
10
Hey frnd here is ur solution...
let first term be 3
& 8th term(last term) term is 24
now it forms a series named A.P
with common difference=3
and total terms (n)=8
hence sum of 8 term will be
n/2{first term+last term}
= 8/2{3+24)
=4{27}
= 108 is required sum
hope this will help you..
let first term be 3
& 8th term(last term) term is 24
now it forms a series named A.P
with common difference=3
and total terms (n)=8
hence sum of 8 term will be
n/2{first term+last term}
= 8/2{3+24)
=4{27}
= 108 is required sum
hope this will help you..
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