Question

find the sum of first 8 multiples of 3

Answer 1

hey mate.,
here's ur answer.
we have, a=3, tn=24,d=3
Therefore Sn=n/2(t1+tn)
S8=8/2(3+24)
S8= 108
hope it helps u..... :)

Answer 2

Answer:

Step-by-step explanation:

First 3multiple 3,6,9,12,......24

a=3

d=6-3=3

Sn=8/2(2×3+(8-1)3)

=5(6+21)

=5×27

=135