Question

find the sum of first 8 multiples of 3 (chapter AP)
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Answer 1

Answer:

3 +6+9+12+15+18+21+24 --

Step-by-step explanation:

108

Answer 2

plzz hit thank n follow if it helps

Step-by-step explanation:

first multiple of 3 (a)= 3

common difference (d)= 3

no of terms (n) =8

sum of terms = n/2 ( 2a+ ( n-1)d)

= 4[ 2×3 + 7×3]

=4[ 6 + 21]

= 4× 27

= 108