find the sum of first 8 multiples of 3 (chapter AP)
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0
Answer:
3 +6+9+12+15+18+21+24 --
Step-by-step explanation:
108
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plzz hit thank n follow if it helps
Step-by-step explanation:
first multiple of 3 (a)= 3
common difference (d)= 3
no of terms (n) =8
sum of terms = n/2 ( 2a+ ( n-1)d)
= 4[ 2×3 + 7×3]
=4[ 6 + 21]
= 4× 27
= 108
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