Question

find the sum of first 8 multiples of 3 please solve this problem​

Answer 1

Answer:

108

Step-by-step explanation:

From Arithmetic Progresses, sum of n terms from 1st term is

n/2[2a+(n-1)d]

In the given question,

first term = first multiple of 3

first term = 3

common difference = 3

Then, applying formula from above.

Assuming the value of n as 8 and a as 3

8/2[2(3)+(8-1)3]

4[6+21]

4(27)

108

Therefore sum of first 8 multiples of 3 is 108.

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..hope this will help u......... :-)

Answer 2

3+6+9+12+15+18+21+24=108