find the sum of first 8 multiples of 4
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2
Answer:
The sum of first 8 multiples of 4:–
4+8+12+16+20+24+28+32=144
hope it will help you....
Answered by
0
Multiples(4):4,8,12,16,24,28,32,36, 40,44,48........
So the eight multiple of 4 is 32.
Let the first multiple be a and the eight multiple be an.
Total terms be n.
According to this,
Sn= n(a+an)/2
=8(4+32)/2=8(36)/2
=> Sn=288/2= 144
So the sum of first 8 multiples of 4 is 144.
Hope this is helpful.
So the eight multiple of 4 is 32.
Let the first multiple be a and the eight multiple be an.
Total terms be n.
According to this,
Sn= n(a+an)/2
=8(4+32)/2=8(36)/2
=> Sn=288/2= 144
So the sum of first 8 multiples of 4 is 144.
Hope this is helpful.
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