Question

Find the sum of first 8 muntiples of 3

Answer 1

First 8 multiples of 3 = 3,6,9,12,15,18,21,24
Their sum = 3 + 6 + 9 + 12 + 15 + 18 + 21 + 24
= 108 Answer
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Answer 2

HEY MATE!

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HERE IS YOUR ANSWER:

STEP BY STEP EXPLANATION:

First multiple of 3=3

so, first term (a)=3

Common difference (d)=3 , as they are multiples of three so each will have a differnce of 3

Number of terms(n)=8...given in the question

Sn=n/2[2a+(n-1)d]

S8=8/2[2×3+(8-1)3]

S8=4[6+(7)3]

S8=4(6+21)

S8=4(27)

S8=108

You can also use another formula

Sn=n/2(a+l)

last term (l)=24 .....8th multiple

So, S8=8/2(3+24)

S8=4(27)

S8=108

Thus , sum of first 8 multiples of 3 is 108.

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HOPE IT HELPED ^_^