Question

Find the sum of first 8 terms of AP whose first term is 3 and common difference is 6.​

Answer 1

Answer:

Given:

a=3, d=6

Sn=n/2(2a+(n-1)d)

S8=4(6+42)

S8=198

Answer 2

here is ur ans ...

n = 8

d = 6

a = 3

so..

Sn = n/2 [2a + (n -1 ) * d ]

:- S8 = 8/2 [ 2*3 + ( 8 - 1 ) * 6 ]

:- S8 = 4 [ 6 + 7*6 ]

:- S8 = 4 [ 6 + 42 ]

:- S8 = 4 * 48

therefore ..

S8 = 192

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