find the sum of first 80 natural number
Answers
Answered by
1
A.P: 1,2,3,4.....80
a=1, d=1, n=80
a^n = a + (n-1)d
= 1 + (80-1)1
= 1 + 79
= 80
S^n = n/2 (a + a^n)
= 80/2 (1 + 80)
= 40(81)
= 3204
Hope it helps!!! :)
Answered by
0
As we know the formula, n/2×(1+n),so according to it
=(80/2)×1+80
=40×81
=3240 answer.
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