Question

Find the sum of first and last term of an ap if its middle term is 8

Answer 1

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Answer 2

Since, there is one middle term, the number of terms is odd.

Let the total number of terms be 'n'

So, the middle term is n+1/2.

Now,

an+1/2 = a + d[(n+1)/2 - 1]

8 = a + [d(n-1)] / 2

8 = [2a + d(n-1)] / 2

16 = 2a + d(n-1)

16 = a + a + d(n-1)

16 = a + an

(Hope this was helpful )