Find the sum of first and last term of an AP whose middle term is 8
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Answered by
15
in an arithmetic progression we have
2( middle term )=sum of first and last terms
so here 2(8)=sum of first and last term
hence 16 is the answer
2( middle term )=sum of first and last terms
so here 2(8)=sum of first and last term
hence 16 is the answer
Answered by
15
a + (n/2-1)d = 8
a+a + (n-1)d= 2a + (n-1)d = 16+d 16+d is answer
2(a+ (n/2-1)d) = 16
2a + dn-2d= 16
a+a + (n-1)d= 2a + (n-1)d = 16+d 16+d is answer
2(a+ (n/2-1)d) = 16
2a + dn-2d= 16
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