Question

Find the sum of first by constituent is divisible by 3

Answer 1

Answer:

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Answer 2

Answer:

Answer

Let n,n+1,n+2 be three consecutive positive integers.

We know that n is of the form 3q,3q+1 or, 3q+2 (As per Euclid Division Lemma),

So, we have the following

Case I When n=3q

In this case, n is divisible by 3 but n+1 and n+2 are not divisible by 3.

Case II When n=3q+1

In this case, n+2=3q+1+2=3(q+1) is divisible by 3 but n and n+1 are not divisible by 3.

Case III When n=3q+2

In this case, n+1=3q+1+2=3(q+1) is divisible by 3 but n and n+2 are not divisible by 3.

Hence one of n,n+1 and n+2 is divisible by 3.

Step-by-step explanation:

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