Question

find the sum of first five primes which are in AP​

Answer 1

Answer:

S(5) = n/2 (2a + 4d)

S(5)= 5/2 (2*5 + 4*6)

S(5)= 5/2 (10+24)

S(5) = 5/2 *34

S(5) = 105

Step-by-step explanation:

A.P.(5,11,17,23,29)

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Answer 2

The sum of first five prime numbers that are in AP is 85.

Step-by-step explanation:

The five prime numbers that are in AP are 5,11,17,23,29.

The first term of the AP is 5

Common difference of the AP is 6.

The sum of n terms of an AP is given by :

$S_n=\dfrac{n}{2}(2a+(n-1)d)$

Here n = 5

$S_n=\dfrac{5}{2}(2\times 5+(5-1)6)\\\\S_n=85$

So, the sum of first five prime numbers that are in AP is 85.

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Arithmetic progression

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