Question

find the sum of first n natural numbers​

Answer 1

Answer:

Here is your answer

Step-by-step explanation:

The natural numbers are 1,2,3,4,... so sum of first n natural numbers as

1 + 2 + 3 + 4 + ... + n

Sn = 1 + 2 + 3 + 4 + ... + n

As we know that

Sn=

n

2

[2a+(n−1)d]

According to 'n' natural numbers

first term = a = 1 and common difference = d = 1

∴ Sn=

n

2

[2×1+(n−1)×1]

Sn=

n

2

[2+n−1]

Sn=

n

2

[n+1]

Answer 2

Answer:

1+2+3+4+5+6+7+8+9=45

Step-by-step explanation:

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