Question

find the sum of first 'n' Natural numbers ​

Answer 1

Answer:

valuue of n ?????????????

Answer 2

Answer:

Sn=1+2+3+....+n

Sn=2n[2a+(n−1)d] where a=1,d=2−1=1

⇒Sn=2n[2×1+(n−1)1]

⇒Sn=2n(n+1)

∴ Sum of first n natural numbers=2n(n+1)

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